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Author Topic: geej66 levels  (Read 3795 times)
geej66
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geej66 levels
« on: August 23, 2007, 05:29:32 PM »

Thought I'd try to make some levels and see how it went.

Tunnel of
Fire
: cokodan
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jnz
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Re: geej66 levels
« Reply #1 on: August 23, 2007, 07:25:03 PM »

For Tunnel of Fire (cokodan): sudonyg.  Nice level.  Took some thinking to figure out how to solve it.
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Rene
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Re: geej66 levels
« Reply #2 on: August 25, 2007, 08:40:39 AM »


For Tunnel of Fire (cokodan): pagigat
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geej66
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Re: geej66 levels
« Reply #3 on: August 28, 2007, 12:17:14 AM »

New puzzle:

Get Me Some F's: dipitib
« Last Edit: August 28, 2007, 01:31:02 AM by geej66 » Logged
adept
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Re: geej66 levels
« Reply #4 on: August 28, 2007, 12:54:45 PM »

Here are your F's : gokakuf

imageI suppose if there were some truly unusual random numbers generated, (no f' generated for about 400 times) this would not work. I have an idea for a different type of solution, but no enough time to try to implement it.
« Last Edit: August 28, 2007, 12:58:16 PM by adept » Logged
jnz
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Re: geej66 levels
« Reply #5 on: August 28, 2007, 01:41:57 PM »

For Get Me Some F's (dipitib): sosaguc
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Rene
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Re: geej66 levels
« Reply #6 on: August 28, 2007, 05:30:43 PM »

For Get Me Some F's (dipitib): vinodac

imageIt's based on the fact that only an F is bigger than all of its mulitples in modulo 16 arithmetic.
« Last Edit: August 28, 2007, 05:38:41 PM by Rene » Logged
jnz
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Re: geej66 levels
« Reply #7 on: August 28, 2007, 08:21:10 PM »

My linear sieve solution for Get Me Some F's was kinda boring, so here's a different solution that's more interesting to watch.
For Get Me Some F's (dipitib): hezyxyb

imageF is the only value such that x > 2x > 4x > 8x > 16x

Rene: nice touch with the gate at the top to preprocess the stream
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jwanders
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Re: geej66 levels
« Reply #8 on: August 29, 2007, 05:26:17 PM »

My solution seem to use a different strategy that the others so far:

Give me some F's (dipitib): vyzikig

imageI'm not sure what the math behind it is, but if you keep doubling random numbers modulo 16, you end up with 8.  Then, if you doubling random numbers modulo 16 keeping only those greater than 8, you get C; finally, keeping only numbers greater than C gives you an E to compare to the original random seem and select F's.
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TTTPPP
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Re: geej66 levels
« Reply #9 on: August 30, 2007, 07:34:12 AM »

jwanders - your solution went wrong the first time I watched it.  I don't know why, it was fine after that.  Here's a screen shot of it sending through an A instead of a C.


Full size image:http://img211.imageshack.us/img211/5411/somefskf3.gif
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jwanders
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Re: geej66 levels
« Reply #10 on: August 30, 2007, 10:12:08 AM »

jwanders - your solution went wrong the first time I watched it.  I don't know why, it was fine after that.  Here's a screen shot of it sending through an A instead of a C.
Hmm... I had that problem in my early attempts due to the "doublers" being feed too quickly, but slowed down the feed because of it... Don't know why that happened  Huh

EDIT: Oh, I see... before an [8] reaches it's first comparator, there are three crates already waiting.  If of those crates two consecutive ones are >8, they'll be fed into the next doubler too quickly.

2nd EDIT: Fixed (with only two components, no less!) kobizad
« Last Edit: August 30, 2007, 10:22:20 AM by jwanders » Logged
Shamil
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Re: geej66 levels
« Reply #11 on: March 07, 2008, 02:44:25 PM »

little late, but here is my solution for Give Me Some F's : gygulel
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geej66
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Re: geej66 levels
« Reply #12 on: May 12, 2008, 03:37:41 AM »

Here are some random levels I never posted for some reason or another.

Pick 7: memuxur
The Labyrinth: dikopyt
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sly
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The Postal Service is the best band ever.

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Re: geej66 levels
« Reply #13 on: May 12, 2008, 06:12:51 AM »

Interesting concept for a puzzle

for dikopyt : bozolen
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Okay, think of a number. Now, scratch that number and think of 0. You're thinking of zero, right? FrEaKy
Werbad
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Re: geej66 levels
« Reply #14 on: May 12, 2008, 11:30:17 AM »

For Pick 7 (memuxur): kaxityl
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